Daily Quiz / QUANTS PRACTICE TESTS / Banking and SSC/RRB 2022 - Quants Practice Test -22.09.2022

Banking and SSC/RRB 2022 - Quants Practice Test -22.09.2022

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Q.1) Directions (Q. 1 – 5) : Find out the missing number in the following number series.

24, ?, 38, 87, 284, 1295
24 × 1 – 13 = 23

23 × 2 – 23 = 38

38 × 3 – 33 = 87

87 × 4 – 43 = 284

284 × 5 – 53 = 1295
Q.2) 64, 96, ?, 216, 324, 486
64 × 1.5 = 96

96 × 1.5 = 144

144 × 1.5 = 216

216 × 1.5 = 324

324 × 1.5 = 486
Q.3) 122, 140, ?, 192, 228, 272, 325


The difference of difference is, 5, 6, 7, 8, …..

The answer is 163.
Q.4) ?, 368, 358, 330, 248, 4
372 – (31 +1) = 368

368 – (32 +1) = 358

358 – (33 +1) = 330

330 – (34 +1) = 248

248 – (35 +1) = 4
Q.5) 48, 24, ?, 48, 192, 1536, 24576
48 × 1/2 = 24

24 × 1 = 24

24 × 2 = 48

48 × 4 = 192

192 × 8 = 1536

1536 × 16 = 24576
Q.6) The least value of 8 cosec2 θ + 25 sin2 θ is:
Given: 8 cosec2 θ + 25 sin2 θ

Formula : If a cosec2 θ + b sin2 θ, then minimum value = 2√ab
Calculation:
Minimum Value of 8 cosec2 θ + 25 sin2 θ = 2√(8 × 25)
Þ 2√200 Þ 2√(100 × 2)
Þ 2 × 10√2
Þ 20√2
Q.7) The diagonal and length of the rectangle is 15 cm and 12 cm respectively. Find the area of the rectangle.


By Pythagoras theorem,

AC2 = AB2 = BC2

BC2 = AC2 – AB2

= 152 – 122

= 225 – 144

BC2 = 81

BC = 9 cm = breadth

Area of the rectangle = ℓ × b sq. units

= 12 × 9 cm2

= 108 cm2
Q.8) 6300 is divided between A, B, C such that A : B = 7 : 5, B : C = 4 : 3. Find the share of B.
A : B = 7 : 5 … (1)

B : C = 4 : 3 … (2)

(1) × 4 (2) × (5)

A : B = 28 : 20

B : C = 20 : 15

A : B : C = 28 : 20 : 15

Let A = 28x, B = 20x, C = 15x

28x + 20x + 15x = 6300

63x = 6300

x = 100

Share of B = 20x

= 20 (100)

B = 2000
Q.9) 15 men can complete a task in 10 days. In how many days can 20 men complete the same task?
We know that

M1 × D1 = M2 × D2

15 × 10 = 20 × D2

D2 = (15 × 10)/20

D2 = 7.5 days
Q.10) Richa travels from A to B at the speed of 15 km/h, from B to C at 20 km/h, and from C to D at 30 km/h. If AB = BC = CD, then find the Richa's average speed.
Richa travels from A to B at the speed = 15 km/hr

Richa travels from B to C at the speed = 20 km/hr

Richa travels from C to D at the speed = 30 km/hr

AB = BC = CD

Formula:

Average speed = Total distance/Total time

Calculation:

Let AB = BC = CD = 60 km (LCM of 15, 20 and 30)

Total distance = 3 × 60 = 180 km

Time taken by Richa to travels from A to B = 60/15 = 4 hrs.

Time taken by Richa to travels from B to C = 60/20 = 3 hrs.

Time taken by Richa to travels from C to D = 60/30 = 2 hrs.

Total time taken by Richa to travels from A to D

= 4 + 3 + 2 = 9 hrs.

Average speed = 180/9 = 20 km/hr.